Gaussian elimination - Your turn#
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A loop is set up like in the figure above. The potential of the battery is \(V = 50\). The resistors have values of \(R_1 = 3\), \(R_2 = 2\), and \(R_3 = 14 / 5\). Find the currents of the network. The equations of the currents in this loop are
\[\begin{split} \begin{align}
I_1 - I_2 - I_3 &= 0 \\
3I_1 + \dfrac{14}{5} I_3 &= 50 \tag{left loop} \\
2I_2 - \dfrac{14}{5} I_3 &= 0 \tag{right loop}
\end{align} \end{split}\]
# TODO: Write your solution below
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